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int len (double x []) {
int n = sizeof (x)/sizeof (x [0]);
return n;
}
int main (void) {
double x [] = {0,1,2,3,4};
int n = len (x []);, but even if I search for "how to pass a pointer" because my understanding is not enough No convincing answer was found.
I'm very happy if someone tells me.
-
Answer # 1
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Unfortunately, it isnotcreated as a function in C.
sizeof (x)isbecause
. The pointerdoes not includeinformation about "size of the area you are pointing to".double x []has the same meaning asdouble * x>Pointer sizeA macro that expands a string on the spot is possible.