This is something i am learning using the jupyter notebook.
If i execute the magic command as follows, pi will be up to the decimal point 3.
The calculation result of numpy is a situation where the notation of the decimal point does not change.
Could you tell me how to solve it?
[in1] import numpy as np from math import pi [in2] % precision 3 [out2] '% .3f' [in3] pi [out3] 3.142 [in4] scores = np.array ([30, 40, 100]) std = np.sqrt (np.var (scores, ddof = 0)) std [out4] 30.912061651652348
np.set_printoptions (precision = 3)
I tried the above but did not improve it.Version
Answer # 1
https://github.com/numpy/numpy/issues/11048It seems similar to what is discussed in
There is a link from https://github.com/numpy/numpy/pull/9201#issuecomment-332609336 ↑.
reprfunction is applied to
numpy.float64, the result should behave in the same way as the built-in Python float type Since it seems to be based on a philosophy, I don't think there is any means (you can only format it yourself).
I had to find out if there was a way to write numpy.float64 for jupyter.
Please forgive me for half the answer.
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