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As planned, you need to get the result like this, a list with the following hero values on the page:
name: "Hero name"
dis: "Hero disadvantaged"
name is written to
disadvantage is written to data-value
Here is the whole html:
<td class="cell-icon" data-value="Outworld Destroyer"><div class="image-container image-container-hero image-container-icon"><a href="/heroes/outworld-destroyer"><img class="image-hero image-icon" data-tooltip-url="/heroes/outworld-destroyer/tooltip" rel="tooltip-remote" src="/assets/heroes/outworld-destroyer-60496afd5b92709cbc2350ddd2257b1d6f0e1ce6dd5b2c6a4614e9ace6d29 title="Outworld Destroyer"/></a></div></td>, <td class="cell-xlarge"><a class="link-type-hero" href="/heroes/outworld-destroyer">Outworld Destroyer</a></td>, <td data-value="2.9031">2.90%<div class="bar bar-default"><div class="segment segment-disadvantage" style="width: 100.00000000000001%;"></div></div></td>, <td data-value="46.0201">46.02%<div class="bar bar-default"><div class="segment segment-win" style="width: 76.92954492645572%;"></div></div></td>, <td data-value="53896">53.896<div class="bar bar-default"><div class="segment segment-match" style="width: 46.159643713600545%;"></div></div></td>
URL= 'https://en.dotabuff.com/heroes/abaddon/counters' It turns out to display only 1 name and that's it.
This is the output:
[{'name': 'Outworld Destroyer'}]
Here is my "code":
def get_html(url, params=None):
r= requests.get(url, headers=HEADERS, params=params)
return r
def get_content(html):
soup= BeautifulSoup(html, 'lxml')
items= soup.find_all('table', class_='sortable')
heroes= []
for item in items:
td= item.td['data-value']
heroes.append({
'name': item.td['data-value']
})
print(heroes)
def parse():
html= get_html(URL)
if html.status_code== 200:
get_content(html.text)
else:
print("error")
I'm inexperienced myself, but I can't find a solution in the guides.
-
Answer # 1
items= soup.find('table', class_='sortable').find_all('tr')[1:]
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What headers are you sending?
Александр2022-01-26 07:54:12